Misunderstood the use of GuildMember in Discord.js due to vague documentation, resulting in tipbot accounts being created accidentally due to getting the wrong Snowflake for the user. The function now takes the user.id of the recipient, preformated to match the tipper, with appropriately adjusted references to the user.
Hopefully this should fix the issues being had though manual recovery of the currency in the accidentally created accounts will still be required. Sorry for the trouble.
Allow for Tipbot to be used privately while still notifying the user that has received the tip, via private message.
Updates the Help message for new usage instructions, fixes misspelling of 'address' and adds a Key for the [ ] and < > syntax, as some users may not understand their usage.
Reworks the subcommand parsing by using a more compact Switch Function. Necessitates the use of 'break;' but is far more compact and legible, presumed the old if else block is from early development with fewer features available. Switch statement should allow for easier expansion.
Modifies doTip() to avoid requiring code duplication, includes two new variables used to indicate that the tip should be done in privacy mode and where the tip value is located in the 'words' array.
Significant change to sendLbc and it's function call, requirement for private message for recipient required User object, thus the function now requires the actual GuildMember object, not only the ID. While this marginally increases overhead, it should also allow access to the send() function for that Guild Member, allowing for private message to be sent. Further the addition of a privacy flag (0 for non-private, 1 for private) was added so that the function can determine whether to send a public or private response. this required updating references to the Guild Member's id to 'member.id', but otherwise operation remains the same until the transaction is completed, following which it will check the privacy flag and if it is set, will privately send the successful tip message to both author and recipient, otherwise it will simply reply via the normal '.reply()' function.
