43e5602ccd
Signed-off-by: Anthony Fieroni <bvbfan@abv.bg>
183 lines
8.5 KiB
Python
Executable file
183 lines
8.5 KiB
Python
Executable file
#!/usr/bin/env python3
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# Copyright (c) 2014-2019 The Bitcoin Core developers
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# Distributed under the MIT software license, see the accompanying
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# file COPYING or http://www.opensource.org/licenses/mit-license.php.
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"""Test the abandontransaction RPC.
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The abandontransaction RPC marks a transaction and all its in-wallet
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descendants as abandoned which allows their inputs to be respent. It can be
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used to replace "stuck" or evicted transactions. It only works on transactions
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which are not included in a block and are not currently in the mempool. It has
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no effect on transactions which are already abandoned.
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"""
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from decimal import Decimal
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from test_framework.test_framework import BitcoinTestFramework
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from test_framework.util import (
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assert_equal,
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assert_raises_rpc_error,
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connect_nodes,
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disconnect_nodes,
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)
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class AbandonConflictTest(BitcoinTestFramework):
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def set_test_params(self):
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self.num_nodes = 2
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self.extra_args = [["-minrelaytxfee=0.00001"], []]
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def skip_test_if_missing_module(self):
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self.skip_if_no_wallet()
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def run_test(self):
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self.nodes[1].generate(100)
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self.sync_blocks()
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balance = self.nodes[0].getbalance()
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txA = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
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txB = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
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txC = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
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self.sync_mempools()
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self.nodes[1].generate(1)
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# Can not abandon non-wallet transaction
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assert_raises_rpc_error(-5, 'Invalid or non-wallet transaction id', lambda: self.nodes[0].abandontransaction(txid='ff' * 32))
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# Can not abandon confirmed transaction
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assert_raises_rpc_error(-5, 'Transaction not eligible for abandonment', lambda: self.nodes[0].abandontransaction(txid=txA))
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self.sync_blocks()
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newbalance = self.nodes[0].getbalance()
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assert balance - newbalance < Decimal("0.00102") #no more than fees lost
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balance = newbalance
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# Disconnect nodes so node0's transactions don't get into node1's mempool
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disconnect_nodes(self.nodes[0], 1)
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# Identify the 10btc outputs
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nA = next(tx_out["vout"] for tx_out in self.nodes[0].gettransaction(txA)["details"] if tx_out["amount"] == Decimal("10"))
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nB = next(tx_out["vout"] for tx_out in self.nodes[0].gettransaction(txB)["details"] if tx_out["amount"] == Decimal("10"))
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nC = next(tx_out["vout"] for tx_out in self.nodes[0].gettransaction(txC)["details"] if tx_out["amount"] == Decimal("10"))
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inputs = []
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# spend 10btc outputs from txA and txB
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inputs.append({"txid": txA, "vout": nA})
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inputs.append({"txid": txB, "vout": nB})
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outputs = {}
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outputs[self.nodes[0].getnewaddress()] = Decimal("14.99998")
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outputs[self.nodes[1].getnewaddress()] = Decimal("5")
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signed = self.nodes[0].signrawtransactionwithwallet(self.nodes[0].createrawtransaction(inputs, outputs))
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txAB1 = self.nodes[0].sendrawtransaction(signed["hex"])
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# Identify the 14.99998btc output
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nAB = next(tx_out["vout"] for tx_out in self.nodes[0].gettransaction(txAB1)["details"] if tx_out["amount"] == Decimal("14.99998"))
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#Create a child tx spending AB1 and C
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inputs = []
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inputs.append({"txid": txAB1, "vout": nAB})
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inputs.append({"txid": txC, "vout": nC})
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outputs = {}
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outputs[self.nodes[0].getnewaddress()] = Decimal("24.9996")
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signed2 = self.nodes[0].signrawtransactionwithwallet(self.nodes[0].createrawtransaction(inputs, outputs))
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txABC2 = self.nodes[0].sendrawtransaction(signed2["hex"])
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# Create a child tx spending ABC2
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signed3_change = Decimal("24.999")
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inputs = [{"txid": txABC2, "vout": 0}]
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outputs = {self.nodes[0].getnewaddress(): signed3_change}
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signed3 = self.nodes[0].signrawtransactionwithwallet(self.nodes[0].createrawtransaction(inputs, outputs))
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# note tx is never directly referenced, only abandoned as a child of the above
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self.nodes[0].sendrawtransaction(signed3["hex"])
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# In mempool txs from self should increase balance from change
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newbalance = self.nodes[0].getbalance()
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assert_equal(newbalance, balance - Decimal("30") + signed3_change)
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balance = newbalance
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# Restart the node with a higher min relay fee so the parent tx is no longer in mempool
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# TODO: redo with eviction
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self.stop_node(0)
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self.start_node(0, extra_args=["-minrelaytxfee=0.0001"])
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# Verify txs no longer in either node's mempool
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assert_equal(len(self.nodes[0].getrawmempool()), 0)
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assert_equal(len(self.nodes[1].getrawmempool()), 0)
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# Not in mempool txs from self should only reduce balance
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# inputs are still spent, but change not received
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newbalance = self.nodes[0].getbalance()
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assert_equal(newbalance, balance - signed3_change)
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# Unconfirmed received funds that are not in mempool, also shouldn't show
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# up in unconfirmed balance
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unconfbalance = self.nodes[0].getunconfirmedbalance() + self.nodes[0].getbalance()
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assert_equal(unconfbalance, newbalance)
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# Also shouldn't show up in listunspent
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assert not txABC2 in [utxo["txid"] for utxo in self.nodes[0].listunspent(0)]
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balance = newbalance
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# Abandon original transaction and verify inputs are available again
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# including that the child tx was also abandoned
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self.nodes[0].abandontransaction(txAB1)
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newbalance = self.nodes[0].getbalance()
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assert_equal(newbalance, balance + Decimal("30"))
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balance = newbalance
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# Verify that even with a low min relay fee, the tx is not reaccepted from wallet on startup once abandoned
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self.stop_node(0)
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self.start_node(0, extra_args=["-minrelaytxfee=0.00001"])
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assert_equal(len(self.nodes[0].getrawmempool()), 0)
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assert_equal(self.nodes[0].getbalance(), balance)
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# But if it is received again then it is unabandoned
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# And since now in mempool, the change is available
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# But its child tx remains abandoned
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self.nodes[0].sendrawtransaction(signed["hex"])
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newbalance = self.nodes[0].getbalance()
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assert_equal(newbalance, balance - Decimal("20") + Decimal("14.99998"))
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balance = newbalance
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# Send child tx again so it is unabandoned
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self.nodes[0].sendrawtransaction(signed2["hex"])
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newbalance = self.nodes[0].getbalance()
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assert_equal(newbalance, balance - Decimal("10") - Decimal("14.99998") + Decimal("24.9996"))
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balance = newbalance
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# Remove using high relay fee again
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self.stop_node(0)
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self.start_node(0, extra_args=["-minrelaytxfee=0.0001"])
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assert_equal(len(self.nodes[0].getrawmempool()), 0)
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newbalance = self.nodes[0].getbalance()
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assert_equal(newbalance, balance - Decimal("24.9996"))
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balance = newbalance
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# Create a double spend of AB1 by spending again from only A's 10 output
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# Mine double spend from node 1
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inputs = []
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inputs.append({"txid": txA, "vout": nA})
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outputs = {}
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outputs[self.nodes[1].getnewaddress()] = Decimal("9.9999")
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tx = self.nodes[0].createrawtransaction(inputs, outputs)
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signed = self.nodes[0].signrawtransactionwithwallet(tx)
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self.nodes[1].sendrawtransaction(signed["hex"])
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self.nodes[1].generate(1)
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connect_nodes(self.nodes[0], 1)
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self.sync_blocks()
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# Verify that B and C's 10 BTC outputs are available for spending again because AB1 is now conflicted
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newbalance = self.nodes[0].getbalance()
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assert_equal(newbalance, balance + Decimal("20"))
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balance = newbalance
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# There is currently a minor bug around this and so this test doesn't work. See Issue #7315
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# Invalidate the block with the double spend and B's 10 BTC output should no longer be available
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# Don't think C's should either
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self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
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newbalance = self.nodes[0].getbalance()
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#assert_equal(newbalance, balance - Decimal("10"))
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self.log.info("If balance has not declined after invalidateblock then out of mempool wallet tx which is no longer")
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self.log.info("conflicted has not resumed causing its inputs to be seen as spent. See Issue #7315")
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self.log.info(str(balance) + " -> " + str(newbalance) + " ?")
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if __name__ == '__main__':
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AbandonConflictTest().main()
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