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Use typed *Item in DeleteFunc

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Bjørn Erik Pedersen 2020-08-13 16:10:22 +02:00
parent e9b7be5016
commit a42bd4a9c8
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GPG key ID: 330E6E2BD4859D8F
6 changed files with 13 additions and 13 deletions
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4
bucket.go
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@ -54,7 +54,7 @@ func (b *bucket) delete(key string) *Item {
// the item from the map. I'm pretty sure this is 100% fine, but it is unique.
// (We do this so that the write to the channel is under the read lock and not the
// write lock)
func (b *bucket) deleteFunc(matches func(key string, item interface{}) bool, deletables chan *Item) int {
func (b *bucket) deleteFunc(matches func(key string, item *Item) bool, deletables chan *Item) int {
lookup := b.lookup
items := make([]*Item, 0)
@ -81,7 +81,7 @@ func (b *bucket) deleteFunc(matches func(key string, item interface{}) bool, del
}
func (b *bucket) deletePrefix(prefix string, deletables chan *Item) int {
return b.deleteFunc(func(key string, item interface{}) bool {
return b.deleteFunc(func(key string, item *Item) bool {
return strings.HasPrefix(key, prefix)
}, deletables)
}

2
cache.go
View file

@ -64,7 +64,7 @@ func (c *Cache) DeletePrefix(prefix string) int {
}
// Deletes all items that the matches func evaluates to true.
func (c *Cache) DeleteFunc(matches func(key string, item interface{}) bool) int {
func (c *Cache) DeleteFunc(matches func(key string, item *Item) bool) int {
count := 0
for _, b := range c.buckets {
count += b.deleteFunc(matches, c.deletables)

8
cache_test.go
View file

@ -63,17 +63,17 @@ func (_ CacheTests) DeletesAFunc() {
cache.Set("f", 6, time.Minute)
Expect(cache.ItemCount()).To.Equal(6)
Expect(cache.DeleteFunc(func(key string, item interface{}) bool {
Expect(cache.DeleteFunc(func(key string, item *Item) bool {
return false
})).To.Equal(0)
Expect(cache.ItemCount()).To.Equal(6)
Expect(cache.DeleteFunc(func(key string, item interface{}) bool {
return item.(*Item).Value().(int) < 4
Expect(cache.DeleteFunc(func(key string, item *Item) bool {
return item.Value().(int) < 4
})).To.Equal(3)
Expect(cache.ItemCount()).To.Equal(3)
Expect(cache.DeleteFunc(func(key string, item interface{}) bool {
Expect(cache.DeleteFunc(func(key string, item *Item) bool {
return key == "d"
})).To.Equal(1)
Expect(cache.ItemCount()).To.Equal(2)

2
layeredbucket.go
View file

@ -71,7 +71,7 @@ func (b *layeredBucket) deletePrefix(primary, prefix string, deletables chan *It
return bucket.deletePrefix(prefix, deletables)
}
func (b *layeredBucket) deleteFunc(primary string, matches func(key string, item interface{}) bool, deletables chan *Item) int {
func (b *layeredBucket) deleteFunc(primary string, matches func(key string, item *Item) bool, deletables chan *Item) int {
b.RLock()
bucket, exists := b.buckets[primary]
b.RUnlock()

2
layeredcache.go
View file

@ -155,7 +155,7 @@ func (c *LayeredCache) DeletePrefix(primary, prefix string) int {
}
// Deletes all items that share the same primary key and where the matches func evaluates to true.
func (c *LayeredCache) DeleteFunc(primary string, matches func(key string, item interface{}) bool) int {
func (c *LayeredCache) DeleteFunc(primary string, matches func(key string, item *Item) bool) int {
return c.bucket(primary).deleteFunc(primary, matches, c.deletables)
}

8
layeredcache_test.go
View file

@ -107,17 +107,17 @@ func (_ *LayeredCacheTests) DeletesAFunc() {
cache.Set("spice", "f", 6, time.Minute)
Expect(cache.ItemCount()).To.Equal(6)
Expect(cache.DeleteFunc("spice", func(key string, item interface{}) bool {
Expect(cache.DeleteFunc("spice", func(key string, item *Item) bool {
return false
})).To.Equal(0)
Expect(cache.ItemCount()).To.Equal(6)
Expect(cache.DeleteFunc("spice", func(key string, item interface{}) bool {
return item.(*Item).Value().(int) < 4
Expect(cache.DeleteFunc("spice", func(key string, item *Item) bool {
return item.Value().(int) < 4
})).To.Equal(2)
Expect(cache.ItemCount()).To.Equal(4)
Expect(cache.DeleteFunc("spice", func(key string, item interface{}) bool {
Expect(cache.DeleteFunc("spice", func(key string, item *Item) bool {
return key == "d"
})).To.Equal(1)
Expect(cache.ItemCount()).To.Equal(3)