Merge #10942: Eliminate fee overpaying edge case when subtracting fee from recipients
49d903e
Eliminate fee overpaying edge case when subtracting fee from recipients (Alex Morcos)
Pull request description:
I'm not sure if this is the cause of the issue in #10034 , but this was a known edge case. I just didn't realize how simple the fix is.
Could use a couple more eyes to make sure nothing silly can go wrong here, but if we all agree it's this simple, we can add this as another 0.15 bug fix.
Tree-SHA512: db1dd1e83363a3c231267b626d3a388893ee70ba1972056fe2c339c5c9e4fbfd30f7fe837c30cc7be884d454797fd4c619b9d631a8d5eeb55cdb07402a83acb3
This commit is contained in:
commit
2e857bb619
1 changed files with 8 additions and 4 deletions
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@ -2789,10 +2789,6 @@ bool CWallet::CreateTransaction(const std::vector<CRecipient>& vecSend, CWalletT
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// selected to meet nFeeNeeded result in a transaction that
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// requires less fee than the prior iteration.
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// TODO: The case where nSubtractFeeFromAmount > 0 remains
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// to be addressed because it requires returning the fee to
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// the payees and not the change output.
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// If we have no change and a big enough excess fee, then
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// try to construct transaction again only without picking
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// new inputs. We now know we only need the smaller fee
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@ -2819,6 +2815,8 @@ bool CWallet::CreateTransaction(const std::vector<CRecipient>& vecSend, CWalletT
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else if (!pick_new_inputs) {
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// This shouldn't happen, we should have had enough excess
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// fee to pay for the new output and still meet nFeeNeeded
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// Or we should have just subtracted fee from recipients and
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// nFeeNeeded should not have changed
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strFailReason = _("Transaction fee and change calculation failed");
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return false;
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}
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@ -2835,6 +2833,12 @@ bool CWallet::CreateTransaction(const std::vector<CRecipient>& vecSend, CWalletT
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}
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}
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// If subtracting fee from recipients, we now know what fee we
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// need to subtract, we have no reason to reselect inputs
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if (nSubtractFeeFromAmount > 0) {
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pick_new_inputs = false;
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}
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// Include more fee and try again.
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nFeeRet = nFeeNeeded;
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continue;
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