Eliminate fee overpaying edge case when subtracting fee from recipients
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0b11a07848
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49d903e696
1 changed files with 8 additions and 4 deletions
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@ -2774,10 +2774,6 @@ bool CWallet::CreateTransaction(const std::vector<CRecipient>& vecSend, CWalletT
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// selected to meet nFeeNeeded result in a transaction that
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// selected to meet nFeeNeeded result in a transaction that
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// requires less fee than the prior iteration.
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// requires less fee than the prior iteration.
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// TODO: The case where nSubtractFeeFromAmount > 0 remains
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// to be addressed because it requires returning the fee to
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// the payees and not the change output.
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// If we have no change and a big enough excess fee, then
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// If we have no change and a big enough excess fee, then
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// try to construct transaction again only without picking
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// try to construct transaction again only without picking
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// new inputs. We now know we only need the smaller fee
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// new inputs. We now know we only need the smaller fee
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@ -2804,6 +2800,8 @@ bool CWallet::CreateTransaction(const std::vector<CRecipient>& vecSend, CWalletT
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else if (!pick_new_inputs) {
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else if (!pick_new_inputs) {
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// This shouldn't happen, we should have had enough excess
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// This shouldn't happen, we should have had enough excess
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// fee to pay for the new output and still meet nFeeNeeded
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// fee to pay for the new output and still meet nFeeNeeded
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// Or we should have just subtracted fee from recipients and
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// nFeeNeeded should not have changed
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strFailReason = _("Transaction fee and change calculation failed");
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strFailReason = _("Transaction fee and change calculation failed");
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return false;
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return false;
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}
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}
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@ -2820,6 +2818,12 @@ bool CWallet::CreateTransaction(const std::vector<CRecipient>& vecSend, CWalletT
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}
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}
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}
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}
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// If subtracting fee from recipients, we now know what fee we
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// need to subtract, we have no reason to reselect inputs
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if (nSubtractFeeFromAmount > 0) {
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pick_new_inputs = false;
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}
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// Include more fee and try again.
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// Include more fee and try again.
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nFeeRet = nFeeNeeded;
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nFeeRet = nFeeNeeded;
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continue;
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continue;
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