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namespace: drop boost::assign altogether here

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Standard functions are even simpler
This commit is contained in:
Cory Fields 2014-12-19 16:49:00 -05:00
parent a3241998e1
commit 9b1ab860ff
1 changed files with 8 additions and 12 deletions
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20
src/test/multisig_tests.cpp
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@ -15,12 +15,10 @@
#include "wallet_ismine.h"
#endif
#include <boost/assign/std/vector.hpp>
#include <boost/foreach.hpp>
#include <boost/test/unit_test.hpp>
using namespace std;
using namespace boost::assign;
typedef vector<unsigned char> valtype;
@ -81,22 +79,21 @@ BOOST_AUTO_TEST_CASE(multisig_verify)
CScript s;
// Test a AND b:
keys.clear();
keys += key[0],key[1]; // magic operator+= from boost.assign
keys.assign(1,key[0]);
keys.push_back(key[1]);
s = sign_multisig(a_and_b, keys, txTo[0], 0);
BOOST_CHECK(VerifyScript(s, a_and_b, flags, SignatureChecker(txTo[0], 0), &err));
BOOST_CHECK_MESSAGE(err == SCRIPT_ERR_OK, ScriptErrorString(err));
for (int i = 0; i < 4; i++)
{
keys.clear();
keys += key[i];
keys.assign(1,key[i]);
s = sign_multisig(a_and_b, keys, txTo[0], 0);
BOOST_CHECK_MESSAGE(!VerifyScript(s, a_and_b, flags, SignatureChecker(txTo[0], 0), &err), strprintf("a&b 1: %d", i));
BOOST_CHECK_MESSAGE(err == SCRIPT_ERR_INVALID_STACK_OPERATION, ScriptErrorString(err));
keys.clear();
keys += key[1],key[i];
keys.assign(1,key[1]);
keys.push_back(key[i]);
s = sign_multisig(a_and_b, keys, txTo[0], 0);
BOOST_CHECK_MESSAGE(!VerifyScript(s, a_and_b, flags, SignatureChecker(txTo[0], 0), &err), strprintf("a&b 2: %d", i));
BOOST_CHECK_MESSAGE(err == SCRIPT_ERR_EVAL_FALSE, ScriptErrorString(err));
@ -105,8 +102,7 @@ BOOST_AUTO_TEST_CASE(multisig_verify)
// Test a OR b:
for (int i = 0; i < 4; i++)
{
keys.clear();
keys += key[i];
keys.assign(1,key[i]);
s = sign_multisig(a_or_b, keys, txTo[1], 0);
if (i == 0 || i == 1)
{
@ -132,8 +128,8 @@ BOOST_AUTO_TEST_CASE(multisig_verify)
for (int i = 0; i < 4; i++)
for (int j = 0; j < 4; j++)
{
keys.clear();
keys += key[i],key[j];
keys.assign(1,key[i]);
keys.push_back(key[j]);
s = sign_multisig(escrow, keys, txTo[2], 0);
if (i < j && i < 3 && j < 3)
{