qa: Fix replace-by-fee race condition failures
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1 changed files with 10 additions and 1 deletions
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@ -72,6 +72,10 @@ class ReplaceByFeeTest(BitcoinTestFramework):
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["-mempoolreplacement=0"]]
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["-mempoolreplacement=0"]]
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def run_test(self):
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def run_test(self):
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# Leave IBD and ensure nodes are synced
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self.nodes[0].generate(1)
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self.sync_all()
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make_utxo(self.nodes[0], 1*COIN)
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make_utxo(self.nodes[0], 1*COIN)
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self.log.info("Running test simple doublespend...")
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self.log.info("Running test simple doublespend...")
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@ -110,13 +114,18 @@ class ReplaceByFeeTest(BitcoinTestFramework):
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"""Simple doublespend"""
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"""Simple doublespend"""
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tx0_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
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tx0_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
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# make_utxo may have generated a bunch of blocks, so we need to sync
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# before we can spend the coins generated, or else the resulting
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# transactions might not be accepted by our peers.
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self.sync_all()
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tx1a = CTransaction()
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tx1a = CTransaction()
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tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
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tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
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tx1a_hex = txToHex(tx1a)
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tx1a_hex = txToHex(tx1a)
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tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
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tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
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self.sync_all([self.nodes])
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self.sync_all()
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# Should fail because we haven't changed the fee
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# Should fail because we haven't changed the fee
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tx1b = CTransaction()
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tx1b = CTransaction()
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