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Stop using aliases in the relationship select

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- This caused issues with mysql who doesn't understand the syntax:
  "delete from x as y where y.id = ?"
This commit is contained in:
Aaron L 2017-06-04 12:29:04 -07:00 committed by Alex Grintsvayg
parent 23f245776d
commit e339812027
1 changed files with 6 additions and 5 deletions
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11
templates/06_relationship_to_many.tpl
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@ -16,7 +16,7 @@ func (o *{{$txt.LocalTable.NameGo}}) {{$txt.Function.Name}}G(mods ...qm.QueryMod
{{- if not (eq $txt.Function.Name $txt.ForeignTable.NamePluralGo)}} via {{.ForeignColumn}} column{{- end}}.
func (o *{{$txt.LocalTable.NameGo}}) {{$txt.Function.Name}}(exec boil.Executor, mods ...qm.QueryMod) {{$tableNameSingular}}Query {
queryMods := []qm.QueryMod{
qm.Select("{{id 0 | $dot.Quotes}}.*"),
qm.Select("{{$schemaForeignTable}}.*"),
}
if len(mods) != 0 {
@ -25,17 +25,18 @@ func (o *{{$txt.LocalTable.NameGo}}) {{$txt.Function.Name}}(exec boil.Executor,
{{if .ToJoinTable -}}
queryMods = append(queryMods,
qm.InnerJoin("{{.JoinTable | $dot.SchemaTable}} as {{id 1 | $dot.Quotes}} on {{id 0 | $dot.Quotes}}.{{.ForeignColumn | $dot.Quotes}} = {{id 1 | $dot.Quotes}}.{{.JoinForeignColumn | $dot.Quotes}}"),
qm.Where("{{id 1 | $dot.Quotes}}.{{.JoinLocalColumn | $dot.Quotes}}=?", o.{{$txt.LocalTable.ColumnNameGo}}),
{{$schemaJoinTable := .JoinTable | $.SchemaTable -}}
qm.InnerJoin("{{$schemaJoinTable}} on {{$schemaForeignTable}}.{{.ForeignColumn | $dot.Quotes}} = {{$schemaJoinTable}}.{{.JoinForeignColumn | $dot.Quotes}}"),
qm.Where("{{$schemaJoinTable}}.{{.JoinLocalColumn | $dot.Quotes}}=?", o.{{$txt.LocalTable.ColumnNameGo}}),
)
{{else -}}
queryMods = append(queryMods,
qm.Where("{{id 0 | $dot.Quotes}}.{{.ForeignColumn | $dot.Quotes}}=?", o.{{$txt.LocalTable.ColumnNameGo}}),
qm.Where("{{$schemaForeignTable}}.{{.ForeignColumn | $dot.Quotes}}=?", o.{{$txt.LocalTable.ColumnNameGo}}),
)
{{end}}
query := {{$txt.ForeignTable.NamePluralGo}}(exec, queryMods...)
queries.SetFrom(query.Query, "{{$schemaForeignTable}} as {{id 0 | $dot.Quotes}}")
queries.SetFrom(query.Query, "{{$schemaForeignTable}}")
return query
}