Checks if all licenses are free before marking the software as free
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4 changed files with 28 additions and 5 deletions
8
licenses.json
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8
licenses.json
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@ -0,0 +1,8 @@
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{
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"licenses": [
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"GNU GPL v3.0",
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"GPL3",
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"GPL3+",
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"MIT"
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]
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}
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BIN
modules/__pycache__/render.cpython-310.pyc
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BIN
modules/__pycache__/render.cpython-310.pyc
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BIN
modules/__pycache__/search.cpython-310.pyc
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modules/__pycache__/search.cpython-310.pyc
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@ -7,6 +7,21 @@
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# your ability to set it up and running.
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from modules import search
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import json
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def isFree(licenses):
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matches = 0
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with open("licenses.json", "r") as data:
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all_licenses = json.load(data)
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for license in licenses:
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for license2 in all_licenses["licenses"]:
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if license2 == license:
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matches = matches + 1
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break
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if matches == len(licenses):
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return True
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return False
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def html(page, json):
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@ -18,11 +33,10 @@ def html(page, json):
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# the four essential freedoms.
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free = False
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has_license = False
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if "licenses" in json and json["licenses"]:
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free = True
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has_license = True
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free = isFree(json["licenses"])
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page = page + "\n <h1>"
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try:
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page = page + '\n<img src="'+ json["links"]["icon"] + '" alt="Logo" style="width:50px;">'
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@ -122,7 +136,8 @@ def suggestions(page, json):
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free = False
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if "licenses" in i[-1] and i[-1]["licenses"]:
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free = True
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has_license = True
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free = isFree(i[-1]["licenses"])
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if not i[0] or i[-1] == json or not free:
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continue
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