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batched blockchain.address.subscribe

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This commit is contained in:
Jack Robison 2020-01-09 23:05:49 -05:00
parent 0ee7870bdf
commit 38b108752e
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3 changed files with 36 additions and 13 deletions
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34
lbry/wallet/ledger.py
View file

@ -425,6 +425,7 @@ class Ledger(metaclass=LedgerRegistry):
async def subscribe_accounts(self):
if self.network.is_connected and self.accounts:
log.info("Subscribe to %i accounts", len(self.accounts))
await asyncio.wait([
self.subscribe_account(a) for a in self.accounts
])
@ -444,15 +445,32 @@ class Ledger(metaclass=LedgerRegistry):
AddressesGeneratedEvent(address_manager, addresses)
)
async def subscribe_addresses(self, address_manager: AddressManager, addresses: List[str]):
async def subscribe_addresses(self, address_manager: AddressManager, addresses: List[str], batch_size: int = 1000):
if self.network.is_connected and addresses:
await asyncio.wait([
self.subscribe_address(address_manager, address) for address in addresses
])
async def subscribe_address(self, address_manager: AddressManager, address: str):
remote_status = await self.network.subscribe_address(address)
self._update_tasks.add(self.update_history(address, remote_status, address_manager))
addresses_remaining = list(addresses)
retries = 0
while addresses_remaining:
batch = addresses_remaining[:batch_size]
try:
results = await self.network.rpc('blockchain.address.subscribe', batch, True)
for address, remote_status in zip(batch, results):
self._update_tasks.add(self.update_history(address, remote_status, address_manager))
retries = 0
addresses_remaining = addresses_remaining[batch_size:]
log.info("subscribed to %i/%i addresses", len(addresses) - len(addresses_remaining), len(addresses))
except asyncio.TimeoutError:
if retries >= 3:
log.warning(
"timed out subscribing to addresses from %s:%i",
*self.network.client.server_address_and_port
)
# abort and cancel, we can't lose a subscription, it will happen again on reconnect
if self.network.client:
self.network.client.abort()
raise asyncio.CancelledError()
await asyncio.sleep(1)
retries += 1
log.info("finished subscribing to %i addresses", len(addresses))
def process_status_update(self, update):
address, remote_status = update

5
lbry/wallet/network.py
View file

@ -256,9 +256,10 @@ class Network:
def subscribe_headers(self):
return self.rpc('blockchain.headers.subscribe', [True], True)
async def subscribe_address(self, address):
async def subscribe_address(self, address, *addresses):
addresses = list((address, ) + addresses)
try:
return await self.rpc('blockchain.address.subscribe', [address], True)
return await self.rpc('blockchain.address.subscribe', addresses, True)
except asyncio.TimeoutError:
# abort and cancel, we can't lose a subscription, it will happen again on reconnect
if self.client:

10
lbry/wallet/server/session.py
View file

@ -1141,12 +1141,16 @@ class LBRYElectrumX(SessionBase):
hashX = self.address_to_hashX(address)
return await self.hashX_listunspent(hashX)
async def address_subscribe(self, address):
async def address_subscribe(self, *addresses):
"""Subscribe to an address.
address: the address to subscribe to"""
hashX = self.address_to_hashX(address)
return await self.hashX_subscribe(hashX, address)
if len(addresses) > 1000:
raise RPCError(BAD_REQUEST, f'too many addresses in subscription request: {len(addresses)}')
hashXes = [
(self.address_to_hashX(address), address) for address in addresses
]
return await asyncio.gather(*(self.hashX_subscribe(*args) for args in hashXes))
async def address_unsubscribe(self, address):
"""Unsubscribe an address.