lbcd/btcec/field.go

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// Copyright (c) 2013-2014 The btcsuite developers
2014-01-09 06:51:37 +01:00
// Copyright (c) 2013-2014 Dave Collins
// Use of this source code is governed by an ISC
// license that can be found in the LICENSE file.
package btcec
// References:
// [HAC]: Handbook of Applied Cryptography Menezes, van Oorschot, Vanstone.
// http://cacr.uwaterloo.ca/hac/
// All elliptic curve operations for secp256k1 are done in a finite field
// characterized by a 256-bit prime. Given this precision is larger than the
// biggest available native type, obviously some form of bignum math is needed.
// This package implements specialized fixed-precision field arithmetic rather
// than relying on an arbitrary-precision arithmetic package such as math/big
// for dealing with the field math since the size is known. As a result, rather
// large performance gains are achieved by taking advantage of many
// optimizations not available to arbitrary-precision arithmetic and generic
// modular arithmetic algorithms.
//
// There are various ways to internally represent each finite field element.
// For example, the most obvious representation would be to use an array of 4
// uint64s (64 bits * 4 = 256 bits). However, that representation suffers from
// a couple of issues. First, there is no native Go type large enough to handle
// the intermediate results while adding or multiplying two 64-bit numbers, and
// second there is no space left for overflows when performing the intermediate
// arithmetic between each array element which would lead to expensive carry
// propagation.
//
// Given the above, this implementation represents the the field elements as
// 10 uint32s with each word (array entry) treated as base 2^26. This was
// chosen for the following reasons:
// 1) Most systems at the current time are 64-bit (or at least have 64-bit
// registers available for specialized purposes such as MMX) so the
// intermediate results can typically be done using a native register (and
// using uint64s to avoid the need for additional half-word arithmetic)
// 2) In order to allow addition of the internal words without having to
// propagate the the carry, the max normalized value for each register must
// be less than the number of bits available in the register
// 3) Since we're dealing with 32-bit values, 64-bits of overflow is a
// reasonable choice for #2
// 4) Given the need for 256-bits of precision and the properties stated in #1,
// #2, and #3, the representation which best accommodates this is 10 uint32s
// with base 2^26 (26 bits * 10 = 260 bits, so the final word only needs 22
// bits) which leaves the desired 64 bits (32 * 10 = 320, 320 - 256 = 64) for
// overflow
//
// Since it is so important that the field arithmetic is extremely fast for
// high performance crypto, this package does not perform any validation where
// it ordinarily would. For example, some functions only give the correct
// result is the field is normalized and there is no checking to ensure it is.
// While I typically prefer to ensure all state and input is valid for most
// packages, this code is really only used internally and every extra check
// counts.
import (
"encoding/hex"
)
// Constants used to make the code more readable.
const (
twoBitsMask = 0x3
fourBitsMask = 0xf
sixBitsMask = 0x3f
eightBitsMask = 0xff
)
// Constants related to the field representation.
const (
// fieldWords is the number of words used to internally represent the
// 256-bit value.
fieldWords = 10
// fieldBase is the exponent used to form the numeric base of each word.
// 2^(fieldBase*i) where i is the word position.
fieldBase = 26
// fieldOverflowBits is the minimum number of "overflow" bits for each
// word in the field value.
fieldOverflowBits = 32 - fieldBase
// fieldBaseMask is the mask for the bits in each word needed to
// represent the numeric base of each word (except the most significant
// word).
fieldBaseMask = (1 << fieldBase) - 1
// fieldMSBBits is the number of bits in the most significant word used
// to represent the value.
fieldMSBBits = 256 - (fieldBase * (fieldWords - 1))
// fieldMSBMask is the mask for the bits in the most significant word
// needed to represent the value.
fieldMSBMask = (1 << fieldMSBBits) - 1
// fieldPrimeWordZero is word zero of the secp256k1 prime in the
// internal field representation. It is used during modular reduction
// and negation.
fieldPrimeWordZero = 0x3fffc2f
// fieldPrimeWordOne is word one of the secp256k1 prime in the
// internal field representation. It is used during modular reduction
// and negation.
fieldPrimeWordOne = 0x3ffffbf
)
// fieldVal implements optimized fixed-precision arithmetic over the
// secp256k1 finite field. This means all arithmetic is performed modulo
// 0xfffffffffffffffffffffffffffffffffffffffffffffffffffffffefffffc2f. It
// represents each 256-bit value as 10 32-bit integers in base 2^26. This
// provides 6 bits of overflow in each word (10 bits in the most significant
// word) for a total of 64 bits of overflow (9*6 + 10 = 64). It only implements
// the arithmetic needed for elliptic curve operations.
//
// The following depicts the internal representation:
// -----------------------------------------------------------------
// | n[9] | n[8] | ... | n[0] |
// | 32 bits available | 32 bits available | ... | 32 bits available |
// | 22 bits for value | 26 bits for value | ... | 26 bits for value |
// | 10 bits overflow | 6 bits overflow | ... | 6 bits overflow |
// | Mult: 2^(26*9) | Mult: 2^(26*8) | ... | Mult: 2^(26*0) |
// -----------------------------------------------------------------
//
// For example, consider the number 2^49 + 1. It would be represented as:
// n[0] = 1
// n[1] = 2^23
// n[2..9] = 0
//
// The full 256-bit value is then calculated by looping i from 9..0 and
// doing sum(n[i] * 2^(26i)) like so:
// n[9] * 2^(26*9) = 0 * 2^234 = 0
// n[8] * 2^(26*8) = 0 * 2^208 = 0
// ...
// n[1] * 2^(26*1) = 2^23 * 2^26 = 2^49
// n[0] * 2^(26*0) = 1 * 2^0 = 1
// Sum: 0 + 0 + ... + 2^49 + 1 = 2^49 + 1
type fieldVal struct {
n [10]uint32
}
// String returns the field value as a human-readable hex string.
func (f fieldVal) String() string {
t := new(fieldVal).Set(&f).Normalize()
return hex.EncodeToString(t.Bytes()[:])
}
// Zero sets the field value to zero. A newly created field value is already
// set to zero. This function can be useful to clear an existing field value
// for reuse.
func (f *fieldVal) Zero() {
f.n[0] = 0
f.n[1] = 0
f.n[2] = 0
f.n[3] = 0
f.n[4] = 0
f.n[5] = 0
f.n[6] = 0
f.n[7] = 0
f.n[8] = 0
f.n[9] = 0
}
// Set sets the field value equal to the passed value.
//
// The field value is returned to support chaining. This enables syntax like:
// f := new(fieldVal).Set(f2).Add(1) so that f = f2 + 1 where f2 is not
// modified.
func (f *fieldVal) Set(val *fieldVal) *fieldVal {
*f = *val
return f
}
// SetInt sets the field value to the passed integer. This is a convenience
// function since it is fairly common to perform some arithemetic with small
// native integers.
//
// The field value is returned to support chaining. This enables syntax such
// as f := new(fieldVal).SetInt(2).Mul(f2) so that f = 2 * f2.
func (f *fieldVal) SetInt(ui uint) *fieldVal {
f.Zero()
f.n[0] = uint32(ui)
return f
}
// SetBytes packs the passed 32-byte big-endian value into the internal field
// value representation.
//
// The field value is returned to support chaining. This enables syntax like:
// f := new(fieldVal).SetBytes(byteArray).Mul(f2) so that f = ba * f2.
func (f *fieldVal) SetBytes(b *[32]byte) *fieldVal {
// Pack the 256 total bits across the 10 uint32 words with a max of
// 26-bits per word. This could be done with a couple of for loops,
// but this unrolled version is significantly faster. Benchmarks show
// this is about 34 times faster than the variant which uses loops.
f.n[0] = uint32(b[31]) | uint32(b[30])<<8 | uint32(b[29])<<16 |
(uint32(b[28])&twoBitsMask)<<24
f.n[1] = uint32(b[28])>>2 | uint32(b[27])<<6 | uint32(b[26])<<14 |
(uint32(b[25])&fourBitsMask)<<22
f.n[2] = uint32(b[25])>>4 | uint32(b[24])<<4 | uint32(b[23])<<12 |
(uint32(b[22])&sixBitsMask)<<20
f.n[3] = uint32(b[22])>>6 | uint32(b[21])<<2 | uint32(b[20])<<10 |
uint32(b[19])<<18
f.n[4] = uint32(b[18]) | uint32(b[17])<<8 | uint32(b[16])<<16 |
(uint32(b[15])&twoBitsMask)<<24
f.n[5] = uint32(b[15])>>2 | uint32(b[14])<<6 | uint32(b[13])<<14 |
(uint32(b[12])&fourBitsMask)<<22
f.n[6] = uint32(b[12])>>4 | uint32(b[11])<<4 | uint32(b[10])<<12 |
(uint32(b[9])&sixBitsMask)<<20
f.n[7] = uint32(b[9])>>6 | uint32(b[8])<<2 | uint32(b[7])<<10 |
uint32(b[6])<<18
f.n[8] = uint32(b[5]) | uint32(b[4])<<8 | uint32(b[3])<<16 |
(uint32(b[2])&twoBitsMask)<<24
f.n[9] = uint32(b[2])>>2 | uint32(b[1])<<6 | uint32(b[0])<<14
return f
}
// SetByteSlice packs the passed big-endian value into the internal field value
// representation. Only the first 32-bytes are used. As a result, it is up to
// the caller to ensure numbers of the appropriate size are used or the value
// will be truncated.
//
// The field value is returned to support chaining. This enables syntax like:
// f := new(fieldVal).SetByteSlice(byteSlice)
func (f *fieldVal) SetByteSlice(b []byte) *fieldVal {
var b32 [32]byte
for i := 0; i < len(b); i++ {
if i < 32 {
b32[i+(32-len(b))] = b[i]
}
}
return f.SetBytes(&b32)
}
// SetHex decodes the passed big-endian hex string into the internal field value
// representation. Only the first 32-bytes are used.
//
// The field value is returned to support chaining. This enables syntax like:
// f := new(fieldVal).SetHex("0abc").Add(1) so that f = 0x0abc + 1
func (f *fieldVal) SetHex(hexString string) *fieldVal {
if len(hexString)%2 != 0 {
hexString = "0" + hexString
}
bytes, _ := hex.DecodeString(hexString)
return f.SetByteSlice(bytes)
}
// Normalize normalizes the internal field words into the desired range and
// performs fast modular reduction over the secp256k1 prime by making use of the
// special form of the prime.
func (f *fieldVal) Normalize() *fieldVal {
// The field representation leaves 6 bits of overflow in each
// word so intermediate calculations can be performed without needing
// to propagate the carry to each higher word during the calculations.
// In order to normalize, first we need to "compact" the full 256-bit
// value to the right and treat the additional 64 leftmost bits as
// the magnitude.
m := f.n[0]
t0 := m & fieldBaseMask
m = (m >> fieldBase) + f.n[1]
t1 := m & fieldBaseMask
m = (m >> fieldBase) + f.n[2]
t2 := m & fieldBaseMask
m = (m >> fieldBase) + f.n[3]
t3 := m & fieldBaseMask
m = (m >> fieldBase) + f.n[4]
t4 := m & fieldBaseMask
m = (m >> fieldBase) + f.n[5]
t5 := m & fieldBaseMask
m = (m >> fieldBase) + f.n[6]
t6 := m & fieldBaseMask
m = (m >> fieldBase) + f.n[7]
t7 := m & fieldBaseMask
m = (m >> fieldBase) + f.n[8]
t8 := m & fieldBaseMask
m = (m >> fieldBase) + f.n[9]
t9 := m & fieldMSBMask
m = m >> fieldMSBBits
// At this point, if the magnitude is greater than 0, the overall value
// is greater than the max possible 256-bit value. In particular, it is
// "how many times larger" than the max value it is. Since this field
// is doing arithmetic modulo the secp256k1 prime, we need to perform
// modular reduction over the prime.
//
// Per [HAC] section 14.3.4: Reduction method of moduli of special form,
// when the modulus is of the special form m = b^t - c, highly efficient
// reduction can be achieved.
//
// The secp256k1 prime is equivalent to 2^256 - 4294968273, so it fits
// this criteria.
//
// 4294968273 in field representation (base 2^26) is:
// n[0] = 977
// n[1] = 64
// That is to say (2^26 * 64) + 977 = 4294968273
//
// The algorithm presented in the referenced section typically repeats
// until the quotient is zero. However, due to our field representation
// we already know at least how many times we would need to repeat as
// it's the value currently in m. Thus we can simply multiply the
// magnitude by the field representation of the prime and do a single
// iteration. Notice that nothing will be changed when the magnitude is
// zero, so we could skip this in that case, however always running
// regardless allows it to run in constant time.
r := t0 + m*977
t0 = r & fieldBaseMask
r = (r >> fieldBase) + t1 + m*64
t1 = r & fieldBaseMask
r = (r >> fieldBase) + t2
t2 = r & fieldBaseMask
r = (r >> fieldBase) + t3
t3 = r & fieldBaseMask
r = (r >> fieldBase) + t4
t4 = r & fieldBaseMask
r = (r >> fieldBase) + t5
t5 = r & fieldBaseMask
r = (r >> fieldBase) + t6
t6 = r & fieldBaseMask
r = (r >> fieldBase) + t7
t7 = r & fieldBaseMask
r = (r >> fieldBase) + t8
t8 = r & fieldBaseMask
r = (r >> fieldBase) + t9
t9 = r & fieldMSBMask
// At this point, the result will be in the range 0 <= result <=
// prime + (2^64 - c). Therefore, one more subtraction of the prime
// might be needed if the current result is greater than or equal to the
// prime. The following does the final reduction in constant time.
// Note that the if/else here intentionally does the bitwise OR with
// zero even though it won't change the value to ensure constant time
// between the branches.
var mask int32
if t0 < fieldPrimeWordZero {
mask |= -1
} else {
mask |= 0
}
if t1 < fieldPrimeWordOne {
mask |= -1
} else {
mask |= 0
}
if t2 < fieldBaseMask {
mask |= -1
} else {
mask |= 0
}
if t3 < fieldBaseMask {
mask |= -1
} else {
mask |= 0
}
if t4 < fieldBaseMask {
mask |= -1
} else {
mask |= 0
}
if t5 < fieldBaseMask {
mask |= -1
} else {
mask |= 0
}
if t6 < fieldBaseMask {
mask |= -1
} else {
mask |= 0
}
if t7 < fieldBaseMask {
mask |= -1
} else {
mask |= 0
}
if t8 < fieldBaseMask {
mask |= -1
} else {
mask |= 0
}
if t9 < fieldMSBMask {
mask |= -1
} else {
mask |= 0
}
t0 = t0 - uint32(^mask&fieldPrimeWordZero)
t1 = t1 - uint32(^mask&fieldPrimeWordOne)
t2 = t2 & uint32(mask)
t3 = t3 & uint32(mask)
t4 = t4 & uint32(mask)
t5 = t5 & uint32(mask)
t6 = t6 & uint32(mask)
t7 = t7 & uint32(mask)
t8 = t8 & uint32(mask)
t9 = t9 & uint32(mask)
// Finally, set the normalized and reduced words.
f.n[0] = t0
f.n[1] = t1
f.n[2] = t2
f.n[3] = t3
f.n[4] = t4
f.n[5] = t5
f.n[6] = t6
f.n[7] = t7
f.n[8] = t8
f.n[9] = t9
return f
}
// PutBytes unpacks the field value to a 32-byte big-endian value using the
// passed byte array. There is a similar function, Bytes, which unpacks the
// field value into a new array and returns that. This version is provided
// since it can be useful to cut down on the number of allocations by allowing
// the caller to reuse a buffer.
//
// The field value must be normalized for this function to return the correct
// result.
func (f *fieldVal) PutBytes(b *[32]byte) {
// Unpack the 256 total bits from the 10 uint32 words with a max of
// 26-bits per word. This could be done with a couple of for loops,
// but this unrolled version is a bit faster. Benchmarks show this is
// about 10 times faster than the variant which uses loops.
b[31] = byte(f.n[0] & eightBitsMask)
b[30] = byte((f.n[0] >> 8) & eightBitsMask)
b[29] = byte((f.n[0] >> 16) & eightBitsMask)
b[28] = byte((f.n[0]>>24)&twoBitsMask | (f.n[1]&sixBitsMask)<<2)
b[27] = byte((f.n[1] >> 6) & eightBitsMask)
b[26] = byte((f.n[1] >> 14) & eightBitsMask)
b[25] = byte((f.n[1]>>22)&fourBitsMask | (f.n[2]&fourBitsMask)<<4)
b[24] = byte((f.n[2] >> 4) & eightBitsMask)
b[23] = byte((f.n[2] >> 12) & eightBitsMask)
b[22] = byte((f.n[2]>>20)&sixBitsMask | (f.n[3]&twoBitsMask)<<6)
b[21] = byte((f.n[3] >> 2) & eightBitsMask)
b[20] = byte((f.n[3] >> 10) & eightBitsMask)
b[19] = byte((f.n[3] >> 18) & eightBitsMask)
b[18] = byte(f.n[4] & eightBitsMask)
b[17] = byte((f.n[4] >> 8) & eightBitsMask)
b[16] = byte((f.n[4] >> 16) & eightBitsMask)
b[15] = byte((f.n[4]>>24)&twoBitsMask | (f.n[5]&sixBitsMask)<<2)
b[14] = byte((f.n[5] >> 6) & eightBitsMask)
b[13] = byte((f.n[5] >> 14) & eightBitsMask)
b[12] = byte((f.n[5]>>22)&fourBitsMask | (f.n[6]&fourBitsMask)<<4)
b[11] = byte((f.n[6] >> 4) & eightBitsMask)
b[10] = byte((f.n[6] >> 12) & eightBitsMask)
b[9] = byte((f.n[6]>>20)&sixBitsMask | (f.n[7]&twoBitsMask)<<6)
b[8] = byte((f.n[7] >> 2) & eightBitsMask)
b[7] = byte((f.n[7] >> 10) & eightBitsMask)
b[6] = byte((f.n[7] >> 18) & eightBitsMask)
b[5] = byte(f.n[8] & eightBitsMask)
b[4] = byte((f.n[8] >> 8) & eightBitsMask)
b[3] = byte((f.n[8] >> 16) & eightBitsMask)
b[2] = byte((f.n[8]>>24)&twoBitsMask | (f.n[9]&sixBitsMask)<<2)
b[1] = byte((f.n[9] >> 6) & eightBitsMask)
b[0] = byte((f.n[9] >> 14) & eightBitsMask)
}
// Bytes unpacks the field value to a 32-byte big-endian value. See PutBytes
// for a variant that allows the a buffer to be passed which can be useful to
// to cut down on the number of allocations by allowing the caller to reuse a
// buffer.
//
// The field value must be normalized for this function to return correct
// result.
func (f *fieldVal) Bytes() *[32]byte {
b := new([32]byte)
f.PutBytes(b)
return b
}
// IsZero returns whether or not the field value is equal to zero.
func (f *fieldVal) IsZero() bool {
// The value can only be zero if no bits are set in any of the words.
// This is a constant time implementation.
bits := f.n[0] | f.n[1] | f.n[2] | f.n[3] | f.n[4] |
f.n[5] | f.n[6] | f.n[7] | f.n[8] | f.n[9]
return bits == 0
}
// IsOdd returns whether or not the field value is an odd number.
//
// The field value must be normalized for this function to return correct
// result.
func (f *fieldVal) IsOdd() bool {
// Only odd numbers have the bottom bit set.
return f.n[0]&1 == 1
}
// Equals returns whether or not the two field values are the same. Both
// field values being compared must be normalized for this function to return
// the correct result.
func (f *fieldVal) Equals(val *fieldVal) bool {
// Xor only sets bits when they are different, so the two field values
// can only be the same if no bits are set after xoring each word.
// This is a constant time implementation.
bits := (f.n[0] ^ val.n[0]) | (f.n[1] ^ val.n[1]) | (f.n[2] ^ val.n[2]) |
(f.n[3] ^ val.n[3]) | (f.n[4] ^ val.n[4]) | (f.n[5] ^ val.n[5]) |
(f.n[6] ^ val.n[6]) | (f.n[7] ^ val.n[7]) | (f.n[8] ^ val.n[8]) |
(f.n[9] ^ val.n[9])
return bits == 0
}
// NegateVal negates the passed value and stores the result in f. The caller
// must provide the magnitude of the passed value for a correct result.
//
// The field value is returned to support chaining. This enables syntax like:
// f.NegateVal(f2).AddInt(1) so that f = -f2 + 1.
func (f *fieldVal) NegateVal(val *fieldVal, magnitude uint32) *fieldVal {
// Negation in the field is just the prime minus the value. However,
// in order to allow negation against a field value without having to
// normalize/reduce it first, multiply by the magnitude (that is how
// "far" away it is from the normalized value) to adjust. Also, since
// negating a value pushes it one more order of magnitude away from the
// normalized range, add 1 to compensate.
//
// For some intuition here, imagine you're performing mod 12 arithmetic
// (picture a clock) and you are negating the number 7. So you start at
// 12 (which is of course 0 under mod 12) and count backwards (left on
// the clock) 7 times to arrive at 5. Notice this is just 12-7 = 5.
// Now, assume you're starting with 19, which is a number that is
// already larger than the modulus and congruent to 7 (mod 12). When a
// value is already in the desired range, its magnitude is 1. Since 19
// is an additional "step", its magnitude (mod 12) is 2. Since any
// multiple of the modulus is conguent to zero (mod m), the answer can
// be shortcut by simply mulplying the magnitude by the modulus and
// subtracting. Keeping with the example, this would be (2*12)-19 = 5.
f.n[0] = (magnitude+1)*fieldPrimeWordZero - val.n[0]
f.n[1] = (magnitude+1)*fieldPrimeWordOne - val.n[1]
f.n[2] = (magnitude+1)*fieldBaseMask - val.n[2]
f.n[3] = (magnitude+1)*fieldBaseMask - val.n[3]
f.n[4] = (magnitude+1)*fieldBaseMask - val.n[4]
f.n[5] = (magnitude+1)*fieldBaseMask - val.n[5]
f.n[6] = (magnitude+1)*fieldBaseMask - val.n[6]
f.n[7] = (magnitude+1)*fieldBaseMask - val.n[7]
f.n[8] = (magnitude+1)*fieldBaseMask - val.n[8]
f.n[9] = (magnitude+1)*fieldMSBMask - val.n[9]
return f
}
// Negate negates the field value. The existing field value is modified. The
// caller must provide the magnitude of the field value for a correct result.
//
// The field value is returned to support chaining. This enables syntax like:
// f.Negate().AddInt(1) so that f = -f + 1.
func (f *fieldVal) Negate(magnitude uint32) *fieldVal {
return f.NegateVal(f, magnitude)
}
// AddInt adds the passed integer to the existing field value and stores the
// result in f. This is a convenience function since it is fairly common to
// perform some arithemetic with small native integers.
//
// The field value is returned to support chaining. This enables syntax like:
// f.AddInt(1).Add(f2) so that f = f + 1 + f2.
func (f *fieldVal) AddInt(ui uint) *fieldVal {
// Since the field representation intentionally provides overflow bits,
// it's ok to use carryless addition as the carry bit is safely part of
// the word and will be normalized out.
f.n[0] += uint32(ui)
return f
}
// Add adds the passed value to the existing field value and stores the result
// in f.
//
// The field value is returned to support chaining. This enables syntax like:
// f.Add(f2).AddInt(1) so that f = f + f2 + 1.
func (f *fieldVal) Add(val *fieldVal) *fieldVal {
// Since the field representation intentionally provides overflow bits,
// it's ok to use carryless addition as the carry bit is safely part of
// each word and will be normalized out. This could obviously be done
// in a loop, but the unrolled version is faster.
f.n[0] += val.n[0]
f.n[1] += val.n[1]
f.n[2] += val.n[2]
f.n[3] += val.n[3]
f.n[4] += val.n[4]
f.n[5] += val.n[5]
f.n[6] += val.n[6]
f.n[7] += val.n[7]
f.n[8] += val.n[8]
f.n[9] += val.n[9]
return f
}
// Add2 adds the passed two field values together and stores the result in f.
//
// The field value is returned to support chaining. This enables syntax like:
// f3.Add2(f, f2).AddInt(1) so that f3 = f + f2 + 1.
func (f *fieldVal) Add2(val *fieldVal, val2 *fieldVal) *fieldVal {
// Since the field representation intentionally provides overflow bits,
// it's ok to use carryless addition as the carry bit is safely part of
// each word and will be normalized out. This could obviously be done
// in a loop, but the unrolled version is faster.
f.n[0] = val.n[0] + val2.n[0]
f.n[1] = val.n[1] + val2.n[1]
f.n[2] = val.n[2] + val2.n[2]
f.n[3] = val.n[3] + val2.n[3]
f.n[4] = val.n[4] + val2.n[4]
f.n[5] = val.n[5] + val2.n[5]
f.n[6] = val.n[6] + val2.n[6]
f.n[7] = val.n[7] + val2.n[7]
f.n[8] = val.n[8] + val2.n[8]
f.n[9] = val.n[9] + val2.n[9]
return f
}
// MulInt multiplies the field value by the passed int and stores the result in
// f. Note that this function can overflow if multiplying the value by any of
// the individual words exceeds a max uint32. Therefore it is important that
// the caller ensures no overflows will occur before using this function.
//
// The field value is returned to support chaining. This enables syntax like:
// f.MulInt(2).Add(f2) so that f = 2 * f + f2.
func (f *fieldVal) MulInt(val uint) *fieldVal {
// Since each word of the field representation can hold up to
// fieldOverflowBits extra bits which will be normalized out, it's safe
// to multiply each word without using a larger type or carry
// propagation so long as the values won't overflow a uint32. This
// could obviously be done in a loop, but the unrolled version is
// faster.
ui := uint32(val)
f.n[0] *= ui
f.n[1] *= ui
f.n[2] *= ui
f.n[3] *= ui
f.n[4] *= ui
f.n[5] *= ui
f.n[6] *= ui
f.n[7] *= ui
f.n[8] *= ui
f.n[9] *= ui
return f
}
// Mul multiplies the passed value to the existing field value and stores the
// result in f. Note that this function can overflow if multiplying any
// of the individual words exceeds a max uint32. In practice, this means the
// magnitude of either value involved in the multiplication must be a max of
// 8.
//
// The field value is returned to support chaining. This enables syntax like:
// f.Mul(f2).AddInt(1) so that f = (f * f2) + 1.
func (f *fieldVal) Mul(val *fieldVal) *fieldVal {
return f.Mul2(f, val)
}
// Mul2 multiplies the passed two field values together and stores the result
// result in f. Note that this function can overflow if multiplying any of
// the individual words exceeds a max uint32. In practice, this means the
// magnitude of either value involved in the multiplication must be a max of
// 8.
//
// The field value is returned to support chaining. This enables syntax like:
// f3.Mul2(f, f2).AddInt(1) so that f3 = (f * f2) + 1.
func (f *fieldVal) Mul2(val *fieldVal, val2 *fieldVal) *fieldVal {
// This could be done with a couple of for loops and an array to store
// the intermediate terms, but this unrolled version is significantly
// faster.
// Terms for 2^(fieldBase*0).
m := uint64(val.n[0]) * uint64(val2.n[0])
t0 := m & fieldBaseMask
// Terms for 2^(fieldBase*1).
m = (m >> fieldBase) +
uint64(val.n[0])*uint64(val2.n[1]) +
uint64(val.n[1])*uint64(val2.n[0])
t1 := m & fieldBaseMask
// Terms for 2^(fieldBase*2).
m = (m >> fieldBase) +
uint64(val.n[0])*uint64(val2.n[2]) +
uint64(val.n[1])*uint64(val2.n[1]) +
uint64(val.n[2])*uint64(val2.n[0])
t2 := m & fieldBaseMask
// Terms for 2^(fieldBase*3).
m = (m >> fieldBase) +
uint64(val.n[0])*uint64(val2.n[3]) +
uint64(val.n[1])*uint64(val2.n[2]) +
uint64(val.n[2])*uint64(val2.n[1]) +
uint64(val.n[3])*uint64(val2.n[0])
t3 := m & fieldBaseMask
// Terms for 2^(fieldBase*4).
m = (m >> fieldBase) +
uint64(val.n[0])*uint64(val2.n[4]) +
uint64(val.n[1])*uint64(val2.n[3]) +
uint64(val.n[2])*uint64(val2.n[2]) +
uint64(val.n[3])*uint64(val2.n[1]) +
uint64(val.n[4])*uint64(val2.n[0])
t4 := m & fieldBaseMask
// Terms for 2^(fieldBase*5).
m = (m >> fieldBase) +
uint64(val.n[0])*uint64(val2.n[5]) +
uint64(val.n[1])*uint64(val2.n[4]) +
uint64(val.n[2])*uint64(val2.n[3]) +
uint64(val.n[3])*uint64(val2.n[2]) +
uint64(val.n[4])*uint64(val2.n[1]) +
uint64(val.n[5])*uint64(val2.n[0])
t5 := m & fieldBaseMask
// Terms for 2^(fieldBase*6).
m = (m >> fieldBase) +
uint64(val.n[0])*uint64(val2.n[6]) +
uint64(val.n[1])*uint64(val2.n[5]) +
uint64(val.n[2])*uint64(val2.n[4]) +
uint64(val.n[3])*uint64(val2.n[3]) +
uint64(val.n[4])*uint64(val2.n[2]) +
uint64(val.n[5])*uint64(val2.n[1]) +
uint64(val.n[6])*uint64(val2.n[0])
t6 := m & fieldBaseMask
// Terms for 2^(fieldBase*7).
m = (m >> fieldBase) +
uint64(val.n[0])*uint64(val2.n[7]) +
uint64(val.n[1])*uint64(val2.n[6]) +
uint64(val.n[2])*uint64(val2.n[5]) +
uint64(val.n[3])*uint64(val2.n[4]) +
uint64(val.n[4])*uint64(val2.n[3]) +
uint64(val.n[5])*uint64(val2.n[2]) +
uint64(val.n[6])*uint64(val2.n[1]) +
uint64(val.n[7])*uint64(val2.n[0])
t7 := m & fieldBaseMask
// Terms for 2^(fieldBase*8).
m = (m >> fieldBase) +
uint64(val.n[0])*uint64(val2.n[8]) +
uint64(val.n[1])*uint64(val2.n[7]) +
uint64(val.n[2])*uint64(val2.n[6]) +
uint64(val.n[3])*uint64(val2.n[5]) +
uint64(val.n[4])*uint64(val2.n[4]) +
uint64(val.n[5])*uint64(val2.n[3]) +
uint64(val.n[6])*uint64(val2.n[2]) +
uint64(val.n[7])*uint64(val2.n[1]) +
uint64(val.n[8])*uint64(val2.n[0])
t8 := m & fieldBaseMask
// Terms for 2^(fieldBase*9).
m = (m >> fieldBase) +
uint64(val.n[0])*uint64(val2.n[9]) +
uint64(val.n[1])*uint64(val2.n[8]) +
uint64(val.n[2])*uint64(val2.n[7]) +
uint64(val.n[3])*uint64(val2.n[6]) +
uint64(val.n[4])*uint64(val2.n[5]) +
uint64(val.n[5])*uint64(val2.n[4]) +
uint64(val.n[6])*uint64(val2.n[3]) +
uint64(val.n[7])*uint64(val2.n[2]) +
uint64(val.n[8])*uint64(val2.n[1]) +
uint64(val.n[9])*uint64(val2.n[0])
t9 := m & fieldBaseMask
// Terms for 2^(fieldBase*10).
m = (m >> fieldBase) +
uint64(val.n[1])*uint64(val2.n[9]) +
uint64(val.n[2])*uint64(val2.n[8]) +
uint64(val.n[3])*uint64(val2.n[7]) +
uint64(val.n[4])*uint64(val2.n[6]) +
uint64(val.n[5])*uint64(val2.n[5]) +
uint64(val.n[6])*uint64(val2.n[4]) +
uint64(val.n[7])*uint64(val2.n[3]) +
uint64(val.n[8])*uint64(val2.n[2]) +
uint64(val.n[9])*uint64(val2.n[1])
t10 := m & fieldBaseMask
// Terms for 2^(fieldBase*11).
m = (m >> fieldBase) +
uint64(val.n[2])*uint64(val2.n[9]) +
uint64(val.n[3])*uint64(val2.n[8]) +
uint64(val.n[4])*uint64(val2.n[7]) +
uint64(val.n[5])*uint64(val2.n[6]) +
uint64(val.n[6])*uint64(val2.n[5]) +
uint64(val.n[7])*uint64(val2.n[4]) +
uint64(val.n[8])*uint64(val2.n[3]) +
uint64(val.n[9])*uint64(val2.n[2])
t11 := m & fieldBaseMask
// Terms for 2^(fieldBase*12).
m = (m >> fieldBase) +
uint64(val.n[3])*uint64(val2.n[9]) +
uint64(val.n[4])*uint64(val2.n[8]) +
uint64(val.n[5])*uint64(val2.n[7]) +
uint64(val.n[6])*uint64(val2.n[6]) +
uint64(val.n[7])*uint64(val2.n[5]) +
uint64(val.n[8])*uint64(val2.n[4]) +
uint64(val.n[9])*uint64(val2.n[3])
t12 := m & fieldBaseMask
// Terms for 2^(fieldBase*13).
m = (m >> fieldBase) +
uint64(val.n[4])*uint64(val2.n[9]) +
uint64(val.n[5])*uint64(val2.n[8]) +
uint64(val.n[6])*uint64(val2.n[7]) +
uint64(val.n[7])*uint64(val2.n[6]) +
uint64(val.n[8])*uint64(val2.n[5]) +
uint64(val.n[9])*uint64(val2.n[4])
t13 := m & fieldBaseMask
// Terms for 2^(fieldBase*14).
m = (m >> fieldBase) +
uint64(val.n[5])*uint64(val2.n[9]) +
uint64(val.n[6])*uint64(val2.n[8]) +
uint64(val.n[7])*uint64(val2.n[7]) +
uint64(val.n[8])*uint64(val2.n[6]) +
uint64(val.n[9])*uint64(val2.n[5])
t14 := m & fieldBaseMask
// Terms for 2^(fieldBase*15).
m = (m >> fieldBase) +
uint64(val.n[6])*uint64(val2.n[9]) +
uint64(val.n[7])*uint64(val2.n[8]) +
uint64(val.n[8])*uint64(val2.n[7]) +
uint64(val.n[9])*uint64(val2.n[6])
t15 := m & fieldBaseMask
// Terms for 2^(fieldBase*16).
m = (m >> fieldBase) +
uint64(val.n[7])*uint64(val2.n[9]) +
uint64(val.n[8])*uint64(val2.n[8]) +
uint64(val.n[9])*uint64(val2.n[7])
t16 := m & fieldBaseMask
// Terms for 2^(fieldBase*17).
m = (m >> fieldBase) +
uint64(val.n[8])*uint64(val2.n[9]) +
uint64(val.n[9])*uint64(val2.n[8])
t17 := m & fieldBaseMask
// Terms for 2^(fieldBase*18).
m = (m >> fieldBase) + uint64(val.n[9])*uint64(val2.n[9])
t18 := m & fieldBaseMask
// What's left is for 2^(fieldBase*19).
t19 := m >> fieldBase
// At this point, all of the terms are grouped into their respective
// base.
//
// Per [HAC] section 14.3.4: Reduction method of moduli of special form,
// when the modulus is of the special form m = b^t - c, highly efficient
// reduction can be achieved per the provided algorithm.
//
// The secp256k1 prime is equivalent to 2^256 - 4294968273, so it fits
// this criteria.
//
// 4294968273 in field representation (base 2^26) is:
// n[0] = 977
// n[1] = 64
// That is to say (2^26 * 64) + 977 = 4294968273
//
// Since each word is in base 26, the upper terms (t10 and up) start
// at 260 bits (versus the final desired range of 256 bits), so the
// field representation of 'c' from above needs to be adjusted for the
// extra 4 bits by multiplying it by 2^4 = 16. 4294968273 * 16 =
// 68719492368. Thus, the adjusted field representation of 'c' is:
// n[0] = 977 * 16 = 15632
// n[1] = 64 * 16 = 1024
// That is to say (2^26 * 1024) + 15632 = 68719492368
//
// To reduce the final term, t19, the entire 'c' value is needed instead
// of only n[0] because there are no more terms left to handle n[1].
// This means there might be some magnitude left in the upper bits that
// is handled below.
m = t0 + t10*15632
t0 = m & fieldBaseMask
m = (m >> fieldBase) + t1 + t10*1024 + t11*15632
t1 = m & fieldBaseMask
m = (m >> fieldBase) + t2 + t11*1024 + t12*15632
t2 = m & fieldBaseMask
m = (m >> fieldBase) + t3 + t12*1024 + t13*15632
t3 = m & fieldBaseMask
m = (m >> fieldBase) + t4 + t13*1024 + t14*15632
t4 = m & fieldBaseMask
m = (m >> fieldBase) + t5 + t14*1024 + t15*15632
t5 = m & fieldBaseMask
m = (m >> fieldBase) + t6 + t15*1024 + t16*15632
t6 = m & fieldBaseMask
m = (m >> fieldBase) + t7 + t16*1024 + t17*15632
t7 = m & fieldBaseMask
m = (m >> fieldBase) + t8 + t17*1024 + t18*15632
t8 = m & fieldBaseMask
m = (m >> fieldBase) + t9 + t18*1024 + t19*68719492368
t9 = m & fieldMSBMask
m = m >> fieldMSBBits
// At this point, if the magnitude is greater than 0, the overall value
// is greater than the max possible 256-bit value. In particular, it is
// "how many times larger" than the max value it is.
//
// The algorithm presented in [HAC] section 14.3.4 repeats until the
// quotient is zero. However, due to the above, we already know at
// least how many times we would need to repeat as it's the value
// currently in m. Thus we can simply multiply the magnitude by the
// field representation of the prime and do a single iteration. Notice
// that nothing will be changed when the magnitude is zero, so we could
// skip this in that case, however always running regardless allows it
// to run in constant time. The final result will be in the range
// 0 <= result <= prime + (2^64 - c), so it is guaranteed to have a
// magnitude of 1, but it is denormalized.
d := t0 + m*977
f.n[0] = uint32(d & fieldBaseMask)
d = (d >> fieldBase) + t1 + m*64
f.n[1] = uint32(d & fieldBaseMask)
f.n[2] = uint32((d >> fieldBase) + t2)
f.n[3] = uint32(t3)
f.n[4] = uint32(t4)
f.n[5] = uint32(t5)
f.n[6] = uint32(t6)
f.n[7] = uint32(t7)
f.n[8] = uint32(t8)
f.n[9] = uint32(t9)
return f
}
// Square squares the field value. The existing field value is modified. Note
// that this function can overflow if multiplying any of the individual words
// exceeds a max uint32. In practice, this means the magnitude of the field
// must be a max of 8 to prevent overflow.
//
// The field value is returned to support chaining. This enables syntax like:
// f.Square().Mul(f2) so that f = f^2 * f2.
func (f *fieldVal) Square() *fieldVal {
return f.SquareVal(f)
}
// SquareVal squares the passed value and stores the result in f. Note that
// this function can overflow if multiplying any of the individual words
// exceeds a max uint32. In practice, this means the magnitude of the field
// being squred must be a max of 8 to prevent overflow.
//
// The field value is returned to support chaining. This enables syntax like:
// f3.SquareVal(f).Mul(f) so that f3 = f^2 * f = f^3.
func (f *fieldVal) SquareVal(val *fieldVal) *fieldVal {
// This could be done with a couple of for loops and an array to store
// the intermediate terms, but this unrolled version is significantly
// faster.
// Terms for 2^(fieldBase*0).
m := uint64(val.n[0]) * uint64(val.n[0])
t0 := m & fieldBaseMask
// Terms for 2^(fieldBase*1).
m = (m >> fieldBase) + 2*uint64(val.n[0])*uint64(val.n[1])
t1 := m & fieldBaseMask
// Terms for 2^(fieldBase*2).
m = (m >> fieldBase) +
2*uint64(val.n[0])*uint64(val.n[2]) +
uint64(val.n[1])*uint64(val.n[1])
t2 := m & fieldBaseMask
// Terms for 2^(fieldBase*3).
m = (m >> fieldBase) +
2*uint64(val.n[0])*uint64(val.n[3]) +
2*uint64(val.n[1])*uint64(val.n[2])
t3 := m & fieldBaseMask
// Terms for 2^(fieldBase*4).
m = (m >> fieldBase) +
2*uint64(val.n[0])*uint64(val.n[4]) +
2*uint64(val.n[1])*uint64(val.n[3]) +
uint64(val.n[2])*uint64(val.n[2])
t4 := m & fieldBaseMask
// Terms for 2^(fieldBase*5).
m = (m >> fieldBase) +
2*uint64(val.n[0])*uint64(val.n[5]) +
2*uint64(val.n[1])*uint64(val.n[4]) +
2*uint64(val.n[2])*uint64(val.n[3])
t5 := m & fieldBaseMask
// Terms for 2^(fieldBase*6).
m = (m >> fieldBase) +
2*uint64(val.n[0])*uint64(val.n[6]) +
2*uint64(val.n[1])*uint64(val.n[5]) +
2*uint64(val.n[2])*uint64(val.n[4]) +
uint64(val.n[3])*uint64(val.n[3])
t6 := m & fieldBaseMask
// Terms for 2^(fieldBase*7).
m = (m >> fieldBase) +
2*uint64(val.n[0])*uint64(val.n[7]) +
2*uint64(val.n[1])*uint64(val.n[6]) +
2*uint64(val.n[2])*uint64(val.n[5]) +
2*uint64(val.n[3])*uint64(val.n[4])
t7 := m & fieldBaseMask
// Terms for 2^(fieldBase*8).
m = (m >> fieldBase) +
2*uint64(val.n[0])*uint64(val.n[8]) +
2*uint64(val.n[1])*uint64(val.n[7]) +
2*uint64(val.n[2])*uint64(val.n[6]) +
2*uint64(val.n[3])*uint64(val.n[5]) +
uint64(val.n[4])*uint64(val.n[4])
t8 := m & fieldBaseMask
// Terms for 2^(fieldBase*9).
m = (m >> fieldBase) +
2*uint64(val.n[0])*uint64(val.n[9]) +
2*uint64(val.n[1])*uint64(val.n[8]) +
2*uint64(val.n[2])*uint64(val.n[7]) +
2*uint64(val.n[3])*uint64(val.n[6]) +
2*uint64(val.n[4])*uint64(val.n[5])
t9 := m & fieldBaseMask
// Terms for 2^(fieldBase*10).
m = (m >> fieldBase) +
2*uint64(val.n[1])*uint64(val.n[9]) +
2*uint64(val.n[2])*uint64(val.n[8]) +
2*uint64(val.n[3])*uint64(val.n[7]) +
2*uint64(val.n[4])*uint64(val.n[6]) +
uint64(val.n[5])*uint64(val.n[5])
t10 := m & fieldBaseMask
// Terms for 2^(fieldBase*11).
m = (m >> fieldBase) +
2*uint64(val.n[2])*uint64(val.n[9]) +
2*uint64(val.n[3])*uint64(val.n[8]) +
2*uint64(val.n[4])*uint64(val.n[7]) +
2*uint64(val.n[5])*uint64(val.n[6])
t11 := m & fieldBaseMask
// Terms for 2^(fieldBase*12).
m = (m >> fieldBase) +
2*uint64(val.n[3])*uint64(val.n[9]) +
2*uint64(val.n[4])*uint64(val.n[8]) +
2*uint64(val.n[5])*uint64(val.n[7]) +
uint64(val.n[6])*uint64(val.n[6])
t12 := m & fieldBaseMask
// Terms for 2^(fieldBase*13).
m = (m >> fieldBase) +
2*uint64(val.n[4])*uint64(val.n[9]) +
2*uint64(val.n[5])*uint64(val.n[8]) +
2*uint64(val.n[6])*uint64(val.n[7])
t13 := m & fieldBaseMask
// Terms for 2^(fieldBase*14).
m = (m >> fieldBase) +
2*uint64(val.n[5])*uint64(val.n[9]) +
2*uint64(val.n[6])*uint64(val.n[8]) +
uint64(val.n[7])*uint64(val.n[7])
t14 := m & fieldBaseMask
// Terms for 2^(fieldBase*15).
m = (m >> fieldBase) +
2*uint64(val.n[6])*uint64(val.n[9]) +
2*uint64(val.n[7])*uint64(val.n[8])
t15 := m & fieldBaseMask
// Terms for 2^(fieldBase*16).
m = (m >> fieldBase) +
2*uint64(val.n[7])*uint64(val.n[9]) +
uint64(val.n[8])*uint64(val.n[8])
t16 := m & fieldBaseMask
// Terms for 2^(fieldBase*17).
m = (m >> fieldBase) + 2*uint64(val.n[8])*uint64(val.n[9])
t17 := m & fieldBaseMask
// Terms for 2^(fieldBase*18).
m = (m >> fieldBase) + uint64(val.n[9])*uint64(val.n[9])
t18 := m & fieldBaseMask
// What's left is for 2^(fieldBase*19).
t19 := m >> fieldBase
// At this point, all of the terms are grouped into their respective
// base.
//
// Per [HAC] section 14.3.4: Reduction method of moduli of special form,
// when the modulus is of the special form m = b^t - c, highly efficient
// reduction can be achieved per the provided algorithm.
//
// The secp256k1 prime is equivalent to 2^256 - 4294968273, so it fits
// this criteria.
//
// 4294968273 in field representation (base 2^26) is:
// n[0] = 977
// n[1] = 64
// That is to say (2^26 * 64) + 977 = 4294968273
//
// Since each word is in base 26, the upper terms (t10 and up) start
// at 260 bits (versus the final desired range of 256 bits), so the
// field representation of 'c' from above needs to be adjusted for the
// extra 4 bits by multiplying it by 2^4 = 16. 4294968273 * 16 =
// 68719492368. Thus, the adjusted field representation of 'c' is:
// n[0] = 977 * 16 = 15632
// n[1] = 64 * 16 = 1024
// That is to say (2^26 * 1024) + 15632 = 68719492368
//
// To reduce the final term, t19, the entire 'c' value is needed instead
// of only n[0] because there are no more terms left to handle n[1].
// This means there might be some magnitude left in the upper bits that
// is handled below.
m = t0 + t10*15632
t0 = m & fieldBaseMask
m = (m >> fieldBase) + t1 + t10*1024 + t11*15632
t1 = m & fieldBaseMask
m = (m >> fieldBase) + t2 + t11*1024 + t12*15632
t2 = m & fieldBaseMask
m = (m >> fieldBase) + t3 + t12*1024 + t13*15632
t3 = m & fieldBaseMask
m = (m >> fieldBase) + t4 + t13*1024 + t14*15632
t4 = m & fieldBaseMask
m = (m >> fieldBase) + t5 + t14*1024 + t15*15632
t5 = m & fieldBaseMask
m = (m >> fieldBase) + t6 + t15*1024 + t16*15632
t6 = m & fieldBaseMask
m = (m >> fieldBase) + t7 + t16*1024 + t17*15632
t7 = m & fieldBaseMask
m = (m >> fieldBase) + t8 + t17*1024 + t18*15632
t8 = m & fieldBaseMask
m = (m >> fieldBase) + t9 + t18*1024 + t19*68719492368
t9 = m & fieldMSBMask
m = m >> fieldMSBBits
// At this point, if the magnitude is greater than 0, the overall value
// is greater than the max possible 256-bit value. In particular, it is
// "how many times larger" than the max value it is.
//
// The algorithm presented in [HAC] section 14.3.4 repeats until the
// quotient is zero. However, due to the above, we already know at
// least how many times we would need to repeat as it's the value
// currently in m. Thus we can simply multiply the magnitude by the
// field representation of the prime and do a single iteration. Notice
// that nothing will be changed when the magnitude is zero, so we could
// skip this in that case, however always running regardless allows it
// to run in constant time. The final result will be in the range
// 0 <= result <= prime + (2^64 - c), so it is guaranteed to have a
// magnitude of 1, but it is denormalized.
n := t0 + m*977
f.n[0] = uint32(n & fieldBaseMask)
n = (n >> fieldBase) + t1 + m*64
f.n[1] = uint32(n & fieldBaseMask)
f.n[2] = uint32((n >> fieldBase) + t2)
f.n[3] = uint32(t3)
f.n[4] = uint32(t4)
f.n[5] = uint32(t5)
f.n[6] = uint32(t6)
f.n[7] = uint32(t7)
f.n[8] = uint32(t8)
f.n[9] = uint32(t9)
return f
}
// Inverse finds the modular multiplicative inverse of the field value. The
// existing field value is modified.
//
// The field value is returned to support chaining. This enables syntax like:
// f.Inverse().Mul(f2) so that f = f^-1 * f2.
func (f *fieldVal) Inverse() *fieldVal {
// Fermat's little theorem states that for a nonzero number a and prime
// prime p, a^(p-1) = 1 (mod p). Since the multipliciative inverse is
// a*b = 1 (mod p), it follows that b = a*a^(p-2) = a^(p-1) = 1 (mod p).
// Thus, a^(p-2) is the multiplicative inverse.
//
// In order to efficiently compute a^(p-2), p-2 needs to be split into
// a sequence of squares and multipications that minimizes the number of
// multiplications needed (since they are more costly than squarings).
// Intermediate results are saved and reused as well.
//
// The secp256k1 prime - 2 is 2^256 - 4294968275.
//
// This has a cost of 258 field squarings and 33 field multiplications.
var a2, a3, a4, a10, a11, a21, a42, a45, a63, a1019, a1023 fieldVal
a2.SquareVal(f)
a3.Mul2(&a2, f)
a4.SquareVal(&a2)
a10.SquareVal(&a4).Mul(&a2)
a11.Mul2(&a10, f)
a21.Mul2(&a10, &a11)
a42.SquareVal(&a21)
a45.Mul2(&a42, &a3)
a63.Mul2(&a42, &a21)
a1019.SquareVal(&a63).Square().Square().Square().Mul(&a11)
a1023.Mul2(&a1019, &a4)
f.Set(&a63) // f = a^(2^6 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^11 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^16 - 1024)
f.Mul(&a1023) // f = a^(2^16 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^21 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^26 - 1024)
f.Mul(&a1023) // f = a^(2^26 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^31 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^36 - 1024)
f.Mul(&a1023) // f = a^(2^36 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^41 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^46 - 1024)
f.Mul(&a1023) // f = a^(2^46 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^51 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^56 - 1024)
f.Mul(&a1023) // f = a^(2^56 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^61 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^66 - 1024)
f.Mul(&a1023) // f = a^(2^66 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^71 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^76 - 1024)
f.Mul(&a1023) // f = a^(2^76 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^81 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^86 - 1024)
f.Mul(&a1023) // f = a^(2^86 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^91 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^96 - 1024)
f.Mul(&a1023) // f = a^(2^96 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^101 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^106 - 1024)
f.Mul(&a1023) // f = a^(2^106 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^111 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^116 - 1024)
f.Mul(&a1023) // f = a^(2^116 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^121 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^126 - 1024)
f.Mul(&a1023) // f = a^(2^126 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^131 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^136 - 1024)
f.Mul(&a1023) // f = a^(2^136 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^141 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^146 - 1024)
f.Mul(&a1023) // f = a^(2^146 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^151 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^156 - 1024)
f.Mul(&a1023) // f = a^(2^156 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^161 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^166 - 1024)
f.Mul(&a1023) // f = a^(2^166 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^171 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^176 - 1024)
f.Mul(&a1023) // f = a^(2^176 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^181 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^186 - 1024)
f.Mul(&a1023) // f = a^(2^186 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^191 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^196 - 1024)
f.Mul(&a1023) // f = a^(2^196 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^201 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^206 - 1024)
f.Mul(&a1023) // f = a^(2^206 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^211 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^216 - 1024)
f.Mul(&a1023) // f = a^(2^216 - 1)
f.Square().Square().Square().Square().Square() // f = a^(2^221 - 32)
f.Square().Square().Square().Square().Square() // f = a^(2^226 - 1024)
f.Mul(&a1019) // f = a^(2^226 - 5)
f.Square().Square().Square().Square().Square() // f = a^(2^231 - 160)
f.Square().Square().Square().Square().Square() // f = a^(2^236 - 5120)
f.Mul(&a1023) // f = a^(2^236 - 4097)
f.Square().Square().Square().Square().Square() // f = a^(2^241 - 131104)
f.Square().Square().Square().Square().Square() // f = a^(2^246 - 4195328)
f.Mul(&a1023) // f = a^(2^246 - 4194305)
f.Square().Square().Square().Square().Square() // f = a^(2^251 - 134217760)
f.Square().Square().Square().Square().Square() // f = a^(2^256 - 4294968320)
return f.Mul(&a45) // f = a^(2^256 - 4294968275) = a^(p-2)
}