Use the noexcept specifier (C++11) instead of deprecated throw()
This commit is contained in:
parent
42307c4bf3
commit
9862550260
2 changed files with 8 additions and 8 deletions
|
@ -26,13 +26,13 @@ struct secure_allocator : public std::allocator<T> {
|
|||
typedef typename base::reference reference;
|
||||
typedef typename base::const_reference const_reference;
|
||||
typedef typename base::value_type value_type;
|
||||
secure_allocator() throw() {}
|
||||
secure_allocator(const secure_allocator& a) throw() : base(a) {}
|
||||
secure_allocator() noexcept {}
|
||||
secure_allocator(const secure_allocator& a) noexcept : base(a) {}
|
||||
template <typename U>
|
||||
secure_allocator(const secure_allocator<U>& a) throw() : base(a)
|
||||
secure_allocator(const secure_allocator<U>& a) noexcept : base(a)
|
||||
{
|
||||
}
|
||||
~secure_allocator() throw() {}
|
||||
~secure_allocator() noexcept {}
|
||||
template <typename _Other>
|
||||
struct rebind {
|
||||
typedef secure_allocator<_Other> other;
|
||||
|
|
|
@ -22,13 +22,13 @@ struct zero_after_free_allocator : public std::allocator<T> {
|
|||
typedef typename base::reference reference;
|
||||
typedef typename base::const_reference const_reference;
|
||||
typedef typename base::value_type value_type;
|
||||
zero_after_free_allocator() throw() {}
|
||||
zero_after_free_allocator(const zero_after_free_allocator& a) throw() : base(a) {}
|
||||
zero_after_free_allocator() noexcept {}
|
||||
zero_after_free_allocator(const zero_after_free_allocator& a) noexcept : base(a) {}
|
||||
template <typename U>
|
||||
zero_after_free_allocator(const zero_after_free_allocator<U>& a) throw() : base(a)
|
||||
zero_after_free_allocator(const zero_after_free_allocator<U>& a) noexcept : base(a)
|
||||
{
|
||||
}
|
||||
~zero_after_free_allocator() throw() {}
|
||||
~zero_after_free_allocator() noexcept {}
|
||||
template <typename _Other>
|
||||
struct rebind {
|
||||
typedef zero_after_free_allocator<_Other> other;
|
||||
|
|
Loading…
Reference in a new issue